What is the derivative of 6/x-2/(x^3+1/(x^4)) ?

The derivative of 6/x-2/(x^3+1/(x^4)) is -6/(x^2)+6/(x^4)-4/(x^5)

What is the first derivative of 6/x-2/(x^3+1/(x^4)) ?

The first derivative of 6/x-2/(x^3+1/(x^4)) is -6/(x^2)+6/(x^4)-4/(x^5)

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\frac{d}{d x} (\frac{6}{x} - \frac{2}{x ^{3}} + \frac{1}{x ^{4}})

- \frac{6}{x ^{2}} + \frac{6}{x ^{4}} - \frac{4}{x ^{5}}

Solution steps

\frac{d}{d x} (\frac{6}{x} - \frac{2}{x ^{3}} + \frac{1}{x ^{4}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{6}{x}) - \frac{d}{d x} (\frac{2}{x ^{3}}) + \frac{d}{d x} (\frac{1}{x ^{4}})

\frac{d}{d x} (\frac{6}{x}) = - \frac{6}{x ^{2}}

\frac{d}{d x} (\frac{2}{x ^{3}}) = - \frac{6}{x ^{4}}

\frac{d}{d x} (\frac{1}{x ^{4}}) = - \frac{4}{x ^{5}}

= - \frac{6}{x ^{2}} - (- \frac{6}{x ^{4}}) - \frac{4}{x ^{5}}

Simplify

= - \frac{6}{x ^{2}} + \frac{6}{x ^{4}} - \frac{4}{x ^{5}}

y = x^{- 8 c o s (x)}

y = sin (t) + \frac{1}{6} e^{t}, (π, \frac{1}{6} e^{π})

\frac{d}{d x} y = x^{4} \cdot x^{5}

\int \frac{( x ^{2} + 1 )}{( x - 8 ) ( x - 7 ) ^{2}} d x

\frac{d}{d x} (x (x^{2} + x + 1)^{3})

What is the derivative of 6/x-2/(x^3+1/(x^4)) ?
The derivative of 6/x-2/(x^3+1/(x^4)) is -6/(x^2)+6/(x^4)-4/(x^5)
What is the first derivative of 6/x-2/(x^3+1/(x^4)) ?
The first derivative of 6/x-2/(x^3+1/(x^4)) is -6/(x^2)+6/(x^4)-4/(x^5)