What is the derivative of f(x)= 3/(\sqrt[4]{x^3)} ?

The derivative of f(x)= 3/(\sqrt[4]{x^3)} is -(9x^2)/(4(x^3)^{5/4)}

What is the first derivative of f(x)= 3/(\sqrt[4]{x^3)} ?

The first derivative of f(x)= 3/(\sqrt[4]{x^3)} is -(9x^2)/(4(x^3)^{5/4)}

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derivative of

- \frac{9 x ^{2}}{4 ( x ^{3} ) ^{\frac{5}{4}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} ((x^{3})^{- \frac{1}{4}})

Apply the chain rule:

- \frac{1}{4 ( x ^{3} ) ^{\frac{5}{4}}} \frac{d}{d x} (x^{3})

= - \frac{1}{4 ( x ^{3} ) ^{\frac{5}{4}}} \frac{d}{d x} (x^{3})

\frac{d}{d x} (x^{3}) = 3 x^{2}

= 3 (- \frac{1}{4 ( x ^{3} ) ^{\frac{5}{4}}} \cdot 3 x^{2})

Simplify

3 (- \frac{1}{4 ( x ^{3} ) ^{\frac{5}{4}}} \cdot 3 x^{2}) : - \frac{9 x ^{2}}{4 ( x ^{3} ) ^{\frac{5}{4}}}

= - \frac{9 x ^{2}}{4 ( x ^{3} ) ^{\frac{5}{4}}}

2 y^{^{'}} = e^{\frac{x}{2}} + y

\int 3^{2 - x} d x

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What is the derivative of f(x)= 3/(\sqrt[4]{x^3)} ?
The derivative of f(x)= 3/(\sqrt[4]{x^3)} is -(9x^2)/(4(x^3)^{5/4)}
What is the first derivative of f(x)= 3/(\sqrt[4]{x^3)} ?
The first derivative of f(x)= 3/(\sqrt[4]{x^3)} is -(9x^2)/(4(x^3)^{5/4)}