What is the derivative of-x^3+3x^2+4 ?

The derivative of-x^3+3x^2+4 is -3x^2+6x

What is the first derivative of-x^3+3x^2+4 ?

The first derivative of-x^3+3x^2+4 is -3x^2+6x

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\frac{d}{d x} (- x^{3} + 3 x^{2} + 4)

- 3 x^{2} + 6 x

Solution steps

\frac{d}{d x} (- x^{3} + 3 x^{2} + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{3}) + \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4) = 0

= - 3 x^{2} + 6 x + 0

Simplify

= - 3 x^{2} + 6 x

y^{^{'}} y^{^{''}} = 2

e^{- 2 t} (3 t)^{2}

\frac{d}{d x} ((f (x) (3 x))^{2} + 5)

x \to 2 lim (5 x^{2} - 3 x + 1)

\frac{d}{d x} (ln (x 4 x - 1))

What is the derivative of-x^3+3x^2+4 ?
The derivative of-x^3+3x^2+4 is -3x^2+6x
What is the first derivative of-x^3+3x^2+4 ?
The first derivative of-x^3+3x^2+4 is -3x^2+6x