What is the derivative of-1+4sin(x) ?

The derivative of-1+4sin(x) is 4cos(x)

What is the first derivative of-1+4sin(x) ?

The first derivative of-1+4sin(x) is 4cos(x)

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\frac{d}{d x} (- 1 + 4 sin (x))

4 cos (x)

Solution steps

\frac{d}{d x} (- 1 + 4 sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (1) + \frac{d}{d x} (4 sin (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (4 sin (x)) = 4 cos (x)

= - 0 + 4 cos (x)

Simplify

= 4 cos (x)

\frac{\partial}{\partial x} (2)

\frac{d y}{d x} = \frac{( 3 x ^{2} + 4 x - 4 )}{2 y - 4}

2 tan (θ)

\frac{d ^{2}}{d x ^{2}} (3 - x^{2})

\frac{d}{d x} ((x - 1)^{5})

What is the derivative of-1+4sin(x) ?
The derivative of-1+4sin(x) is 4cos(x)
What is the first derivative of-1+4sin(x) ?
The first derivative of-1+4sin(x) is 4cos(x)