What is the derivative of (ln(e^x)/x) ?

The derivative of (ln(e^x)/x) is 0

What is the first derivative of (ln(e^x)/x) ?

The first derivative of (ln(e^x)/x) is 0

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\frac{d}{d x} (\frac{ln ( e ^{x} )}{x})

0

Solution steps

\frac{d}{d x} (\frac{ln ( e ^{x} )}{x})

\frac{ln ( e ^{x} )}{x} = 1

= \frac{d}{d x} (1)

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

\int 6 x^{2} + 3 d x

\frac{\partial}{\partial x} (6 x + y)

\int x^{2} + 1 d x

\frac{d}{d x} (\frac{6 x + 4 x ^{2}}{( 3 + 4 x ) ^{2}})

y^{^{'}} + 5 e^{x + y} = 0

What is the derivative of (ln(e^x)/x) ?
The derivative of (ln(e^x)/x) is 0
What is the first derivative of (ln(e^x)/x) ?
The first derivative of (ln(e^x)/x) is 0