What is the tangent of-sin(x) ?

The tangent of-sin(x) is y=-cos(a_{0})x-sin(a_{0})+a_{0}cos(a_{0})

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tangent of-sin(x)

tangent of

- sin (x)

y = - cos (a_{0}) x - sin (a_{0}) + a_{0} cos (a_{0})

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - sin (a_{0}))

Find the slope of

y = - sin (x) : \frac{d y}{d x} = - cos (x)

Compute the slope of

y = - sin (x)

x = a_{0} : m = - cos (a_{0})

Find the line with slope m=

- cos (a_{0})

and passing through

(a_{0}, - sin (a_{0})) : y = - cos (a_{0}) x - sin (a_{0}) + a_{0} cos (a_{0})

y = - cos (a_{0}) x - sin (a_{0}) + a_{0} cos (a_{0})

(\frac{2}{2 s + 1}) - (\frac{1}{s})

(y^{2} + x y) d x - x^{2} d y = 0

\int (\frac{1}{t}) d t

\frac{d}{d x} (5 + 8 x^{\frac{3}{2}})

x \to \infty lim (x \cdot (- 2))

What is the tangent of-sin(x) ?
The tangent of-sin(x) is y=-cos(a_{0})x-sin(a_{0})+a_{0}cos(a_{0})