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Popular >

-y^'-y=e^x

Solution

- y^{^{'}} - y = e^{x}

Solution

y = - \frac{e ^{x}}{2} + \frac{c _{1}}{e ^{x}}

Solution steps

- y^{'} (x) - y = e^{x}

Solve linear ODE:

y = - \frac{e ^{x}}{2} + \frac{c _{1}}{e ^{x}}

y = - \frac{e ^{x}}{2} + \frac{c _{1}}{e ^{x}}

Popular Examples

sum from n=1 to infinity of-1

n = 1 \sum \infty - 1

\frac{d y}{d x} = y + 2

f(x)=4sin(2x)-3cos(3x)

f (x) = 4 sin (2 x) - 3 cos (3 x)

limit as x approaches pi/2 of sin^2(x)

x \to \frac{π}{2} lim (sin^{2} (x))

integral from 1/5 to 7 of 14xln(5x)

\int_{\frac{1}{5}}^{7} 14 x ln (5 x) d x

Frequently Asked Questions (FAQ)

What is the solution for -y^'-y=e^x ?
The solution for -y^'-y=e^x is y=-(e^x)/2+(c_{1})/(e^x)