What is the derivative of 2cos(x+cos^2(x)) ?

The derivative of 2cos(x+cos^2(x)) is -2sin(x)-sin(2x)

What is the first derivative of 2cos(x+cos^2(x)) ?

The first derivative of 2cos(x+cos^2(x)) is -2sin(x)-sin(2x)

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\frac{d}{d x} (2 cos (x) + cos^{2} (x))

- 2 sin (x) - sin (2 x)

Solution steps

\frac{d}{d x} (2 cos (x) + cos^{2} (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 cos (x)) + \frac{d}{d x} (cos^{2} (x))

\frac{d}{d x} (2 cos (x)) = - 2 sin (x)

\frac{d}{d x} (cos^{2} (x)) = - sin (2 x)

= - 2 sin (x) - sin (2 x)

\frac{\partial}{\partial x} (\frac{c ^{2} - x ^{2}}{2 x})

\int \frac{1}{( x ^{2} + 25 ) ^{\frac{5}{2}}} d x

f (t) = e^{t a n (π t)}

y = \frac{6 x ^{2} + 2 x + 6}{x}

\frac{d y}{d x} - 2 x y = 10 x

What is the derivative of 2cos(x+cos^2(x)) ?
The derivative of 2cos(x+cos^2(x)) is -2sin(x)-sin(2x)
What is the first derivative of 2cos(x+cos^2(x)) ?
The first derivative of 2cos(x+cos^2(x)) is -2sin(x)-sin(2x)