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Popular >

2y+xy^'=0

Solution

2 y + x y^{^{'}} = 0

Solution

y = \frac{c _{1}}{x ^{2}}

Solution steps

2 y + x y^{'} (x) = 0

Solve separable ODE:

y = \frac{c _{1}}{x ^{2}}

y = \frac{c _{1}}{x ^{2}}

Popular Examples

derivative of 2/(x^3-3/(x^2))

\frac{d}{d x} (\frac{2}{x ^{3}} - \frac{3}{x ^{2}})

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\frac{d}{d x} (\frac{2}{( x ^{2} + x + 1 ) ^{2}})

(\partial)/(\partial y)(2y+1)

\frac{\partial}{\partial y} (2 y + 1)

derivative of (t+1)^3sqrt(t^2+84)derivative of

(t + 1)^{3} t^{2} + 84

derivative of x^2arctan(2x)derivative of

x^{2} arctan (2 x)

Frequently Asked Questions (FAQ)

What is the solution for 2y+xy^'=0 ?
The solution for 2y+xy^'=0 is y=(c_{1})/(x^2)