What is the limit as x approaches-1 of x^2-4+(x^2-9)^{1/3} ?

The limit as x approaches-1 of x^2-4+(x^2-9)^{1/3} is 2(-1)^{1/3}-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches-1 of x^2-4+(x^2-9)^{1/3}

x \to - 1 lim (x^{2} - 4 + (x^{2} - 9)^{\frac{1}{3}})

2 (- 1)^{\frac{1}{3}} - 3

Solution steps

x \to - 1 lim (x^{2} - 4 + (x^{2} - 9)^{\frac{1}{3}})

Plug in the value

x = - 1

= (- 1)^{2} - 4 + ((- 1)^{2} - 9)^{\frac{1}{3}}

Simplify

(- 1)^{2} - 4 + ((- 1)^{2} - 9)^{\frac{1}{3}} : 2 (- 1)^{\frac{1}{3}} - 3

= 2 (- 1)^{\frac{1}{3}} - 3

n = 0 \sum \infty n (n - 1) x^{n}

\int \frac{4}{x ^{- 1} + 1} d x

\int_{- 2}^{- 1} (- 2 x + 1) d x

\int_{- 1}^{0} π (1 - x^{2})^{2} d x

What is the limit as x approaches-1 of x^2-4+(x^2-9)^{1/3} ?
The limit as x approaches-1 of x^2-4+(x^2-9)^{1/3} is 2(-1)^{1/3}-3