What is (\partial)/(\partial z)(e^{xy}-z) ?

The answer to (\partial)/(\partial z)(e^{xy}-z) is -1

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(\partial)/(\partial z)(e^{xy}-z)

\frac{\partial}{\partial z} (e^{x y} - z)

- 1

Solution steps

\frac{\partial}{\partial z} (e^{x y} - z)

Treat

x, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (e^{x y}) - \frac{\partial}{\partial z} (z)

\frac{\partial}{\partial z} (e^{x y}) = 0

\frac{\partial}{\partial z} (z) = 1

= 0 - 1

Simplify

= - 1

\frac{d}{d t} (\infty (t) + ln (t) + 1)

\frac{\partial}{\partial y} (\frac{y}{x ^{2} + y ^{2} + z ^{2}})

\int \frac{1}{2 x ^{2} + x} d x

\frac{d}{d x} ((cos (x))^{s i n (x)})

e^{x}, 14 e^{- x} + 5, x = 0

What is (\partial)/(\partial z)(e^{xy}-z) ?
The answer to (\partial)/(\partial z)(e^{xy}-z) is -1