What is the derivative of tan^2(1+x) ?

The derivative of tan^2(1+x) is 2tan(1+x)sec^2(1+x)

What is the first derivative of tan^2(1+x) ?

The first derivative of tan^2(1+x) is 2tan(1+x)sec^2(1+x)

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\frac{d}{d x} (tan^{2} (1 + x))

2 tan (1 + x) sec^{2} (1 + x)

Solution steps

\frac{d}{d x} (tan^{2} (1 + x))

Apply the chain rule:

2 tan (1 + x) \frac{d}{d x} (tan (1 + x))

= 2 tan (1 + x) \frac{d}{d x} (tan (1 + x))

\frac{d}{d x} (tan (1 + x)) = sec^{2} (1 + x)

= 2 tan (1 + x) sec^{2} (1 + x)

\int 2 t e^{- s t} d t

\frac{d}{d x} (3 x - sin^{2} (x))

\int x^{2} e^{8 x} d x

\int_{0}^{6} \frac{1}{x ^{2} - 36} d x

\int e^{x} x - e^{x} d x

What is the derivative of tan^2(1+x) ?
The derivative of tan^2(1+x) is 2tan(1+x)sec^2(1+x)
What is the first derivative of tan^2(1+x) ?
The first derivative of tan^2(1+x) is 2tan(1+x)sec^2(1+x)