What is the derivative of ln(4x+3) ?

The derivative of ln(4x+3) is 4/(4x+3)

What is the first derivative of ln(4x+3) ?

The first derivative of ln(4x+3) is 4/(4x+3)

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\frac{d}{d x} (ln (4 x + 3))

\frac{4}{4 x + 3}

Solution steps

\frac{d}{d x} (ln (4 x + 3))

Apply the chain rule:

\frac{1}{4 x + 3} \frac{d}{d x} (4 x + 3)

= \frac{1}{4 x + 3} \frac{d}{d x} (4 x + 3)

\frac{d}{d x} (4 x + 3) = 4

= \frac{1}{4 x + 3} \cdot 4

Simplify

\frac{1}{4 x + 3} \cdot 4 : \frac{4}{4 x + 3}

= \frac{4}{4 x + 3}

\frac{d}{d x} (\frac{( x ^{2} - 1 ) ^{3}}{x ^{2} + 1})

(8 x^{2} - 13 x) e^{x}

\frac{\partial}{\partial x} ((x - y) e^{- x^{2} - y^{2}})

sin (5 t)

y^{^{''}} - y^{^{'}} - 2 y = 8 e - t

What is the derivative of ln(4x+3) ?
The derivative of ln(4x+3) is 4/(4x+3)
What is the first derivative of ln(4x+3) ?
The first derivative of ln(4x+3) is 4/(4x+3)