What is the derivative of log_{4}(e^{2x}) ?

The derivative of log_{4}(e^{2x}) is 2log_{4}(e)

What is the first derivative of log_{4}(e^{2x}) ?

The first derivative of log_{4}(e^{2x}) is 2log_{4}(e)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

lo g_{4} (e^{2 x})

2 lo g_{4} (e)

Solution steps

\frac{d}{d x} (lo g_{4} (e^{2 x}))

Simplify

lo g_{4} (e^{2 x}) : 2 lo g_{4} (e) x

= \frac{d}{d x} (2 lo g_{4} (e) x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 lo g_{4} (e) \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= 2 lo g_{4} (e) \cdot 1

Simplify

= 2 lo g_{4} (e)

\frac{d}{d x} (arccos (- \frac{x}{3}))

x \to 0 - lim (\frac{x ^{2}}{6} - \frac{9}{x})

\frac{d}{d x} (x e^{x} sin (x))

\frac{d}{d x} ((3 x + 4)^{4})

\frac{d}{d x} (3 cosh (3 x) - sinh (3 x))

What is the derivative of log_{4}(e^{2x}) ?
The derivative of log_{4}(e^{2x}) is 2log_{4}(e)
What is the first derivative of log_{4}(e^{2x}) ?
The first derivative of log_{4}(e^{2x}) is 2log_{4}(e)