What is the solution for x^2(dy)/(dx)=y-yx ?

The solution for x^2(dy)/(dx)=y-yx is y=(e^{(-1+c_{1}x)/x})/(x)

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x^2(dy)/(dx)=y-yx

x^{2} \frac{d y}{d x} = y - y x

y = \frac{e ^{\frac{- 1 + c _{1} x}{x}}}{x}

Solution steps

x^{2} \frac{d y}{d x} = y - y x

Solve separable ODE:

y = \frac{e ^{\frac{- 1 + c _{1} x}{x}}}{x}

y = \frac{e ^{\frac{- 1 + c _{1} x}{x}}}{x}

\frac{\partial}{\partial y} (y cos (x y))

x \to \infty lim (\frac{14}{x})

(\frac{( x - 6 )}{( x + 7 )})^{3}

x \to 0 lim (ln (\frac{x}{1 - x}))

h (t) = (t + 3)^{\frac{2}{3}} (2 t^{2} - 4)^{3}

What is the solution for x^2(dy)/(dx)=y-yx ?
The solution for x^2(dy)/(dx)=y-yx is y=(e^{(-1+c_{1}x)/x})/(x)