What is area x^2+2x+2,3x+8,[0,2] ?

The answer to area x^2+2x+2,3x+8,[0,2] is 34/3

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area x^2+2x+2,3x+8,[0,2]

area

x^{2} + 2 x + 2, 3 x + 8, [0, 2]

\frac{34}{3}

Decimal Notation

11.33333 \dots

Solution steps

Apply the area formula:

\int_{0}^{2} x^{2} + 2 x + 2 - (3 x + 8) d x

Solve

\int_{0}^{2} x^{2} + 2 x + 2 - (3 x + 8) d x : \frac{34}{3}

The area is:

= \frac{34}{3}

x \to 2 lim (x^{2} + 5)

\int_{0}^{1} \frac{a x}{x ^{2} - p x} d x

\int 3 x^{2} + 8 x - 2 d x

\frac{\partial}{\partial t} (t^{4} cos (s))

csc^{3} (5 x^{2} + 1)

What is area x^2+2x+2,3x+8,[0,2] ?
The answer to area x^2+2x+2,3x+8,[0,2] is 34/3