What is (\partial)/(\partial u)(3sin(v)cos(u)) ?

The answer to (\partial)/(\partial u)(3sin(v)cos(u)) is -3sin(v)sin(u)

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(\partial)/(\partial u)(3sin(v)cos(u))

\frac{\partial}{\partial u} (3 sin (v) cos (u))

- 3 sin (v) sin (u)

Solution steps

\frac{\partial}{\partial u} (3 sin (v) cos (u))

Treat

v

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 sin (v) \frac{\partial}{\partial u} (cos (u))

Apply the common derivative:

\frac{\partial}{\partial u} (cos (u)) = - sin (u)

= 3 sin (v) (- sin (u))

Simplify

= - 3 sin (v) sin (u)

\frac{d}{d x} (\frac{3}{4 + x ^{2}})

\frac{( s - 2 )}{s ^{2} ( s - 1 ) ^{2}}

sin (t) cos (x) d t - sin (x) cos (t) d x = 0

y^{2} = x, x = 2 y

\frac{d}{d x} (vx)

What is (\partial)/(\partial u)(3sin(v)cos(u)) ?
The answer to (\partial)/(\partial u)(3sin(v)cos(u)) is -3sin(v)sin(u)