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Popular >

area y=4sqrt(x),y=2x

Solution

area

y = 4 x, y = 2 x

Solution

\frac{16}{3}

+1

Decimal Notation

5.33333 \dots

Solution steps

Apply the area formula:

\int_{0}^{4} 4 x - 2 x d x

Solve

\int_{0}^{4} 4 x - 2 x d x : \frac{16}{3}

The area is:

= \frac{16}{3}

Popular Examples

tangent of y=sqrt(2x+1)tangent of

y = 2 x + 1

integral of x^5sqrt(x^3+7)

\int x^{5} x^{3} + 7 d x

inverse oflaplace 1/((s^2+1)(s^2+25))inverse laplace

\frac{1}{( s ^{2} + 1 ) ( s ^{2} + 25 )}

y^'=((5x^3+y^3))/(xy^2)

y^{^{'}} = \frac{( 5 x ^{3} + y ^{3} )}{x y ^{2}}

derivative of f(x)=sqrt(6x+1)derivative of

f (x) = 6 x + 1

Frequently Asked Questions (FAQ)

What is area y=4sqrt(x),y=2x ?
The answer to area y=4sqrt(x),y=2x is 16/3