What is (\partial)/(\partial y)(3x^2+2y^2) ?

The answer to (\partial)/(\partial y)(3x^2+2y^2) is 4y

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(\partial)/(\partial y)(3x^2+2y^2)

\frac{\partial}{\partial y} (3 x^{2} + 2 y^{2})

4 y

Solution steps

\frac{\partial}{\partial y} (3 x^{2} + 2 y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x^{2}) + \frac{\partial}{\partial y} (2 y^{2})

\frac{\partial}{\partial y} (3 x^{2}) = 0

\frac{\partial}{\partial y} (2 y^{2}) = 4 y

= 0 + 4 y

Simplify

= 4 y

(y + 1) d x + (y - 1) (1 + x^{2}) d y = 0

\frac{\partial}{\partial y} (- 3 y^{4} sin (3 x))

\frac{d}{d x} (4 x^{2} + 5 x - 10)

x^{^{''}} + 9 x^{^{'}} = 27, x (0) = 4, x^{^{'}} (0) = 6

x \to 0 lim (\frac{cos ( 1 )}{x})

What is (\partial)/(\partial y)(3x^2+2y^2) ?
The answer to (\partial)/(\partial y)(3x^2+2y^2) is 4y