What is the integral of (x-14)/(x^2(x+2)) ?

The integral of (x-14)/(x^2(x+2)) is 4ln|x|+7/x-4ln|x+2|+C

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integral of (x-14)/(x^2(x+2))

\int \frac{x - 14}{x ^{2} ( x + 2 )} d x

4 ln ∣ x ∣ + \frac{7}{x} - 4 ln ∣ x + 2 ∣ + C

Solution steps

\int \frac{x - 14}{x ^{2} ( x + 2 )} d x

Take the partial fraction of

\frac{x - 14}{x ^{2} ( x + 2 )} : \frac{4}{x} - \frac{7}{x ^{2}} - \frac{4}{x + 2}

= \int \frac{4}{x} - \frac{7}{x ^{2}} - \frac{4}{x + 2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{4}{x} d x - \int \frac{7}{x ^{2}} d x - \int \frac{4}{x + 2} d x

\int \frac{4}{x} d x = 4 ln ∣ x ∣

\int \frac{7}{x ^{2}} d x = - \frac{7}{x}

\int \frac{4}{x + 2} d x = 4 ln ∣ x + 2 ∣

= 4 ln ∣ x ∣ - (- \frac{7}{x}) - 4 ln ∣ x + 2 ∣

Simplify

= 4 ln ∣ x ∣ + \frac{7}{x} - 4 ln ∣ x + 2 ∣

Add a constant to the solution

= 4 ln ∣ x ∣ + \frac{7}{x} - 4 ln ∣ x + 2 ∣ + C

f (x) = \frac{4}{x + 4}

\int_{2}^{x} t^{5} d t

\int 4 e^{4 x + 5} d x

f (x) = cot (x) tan (x)

x (x + 1) y^{^{'}} + x y = 1

What is the integral of (x-14)/(x^2(x+2)) ?
The integral of (x-14)/(x^2(x+2)) is 4ln|x|+7/x-4ln|x+2|+C