What is the integral from 1 to 3 of sin(x^3+2) ?

The integral from 1 to 3 of sin(x^3+2) is

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integral from 1 to 3 of sin(x^3+2)

\int_{1}^{3} sin (x^{3} + 2) d x

Solution steps

\int_{1}^{3} sin (x^{3} + 2) d x

Rewrite using trig identities

= \int_{1}^{3} cos (x^{3}) sin (2) + cos (2) sin (x^{3}) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} cos (x^{3}) sin (2) d x + \int_{1}^{3} cos (2) sin (x^{3}) d x

\frac{d x}{d t} = 1.5 t - \frac{2 x}{100 + t}

\frac{d}{d t} (e^{t} + 4)

\frac{3}{2} x^{2}, - \frac{1}{2} x^{2} + 2

\int \frac{7 x}{36 x ^{2} + 1} d x

x = 10 - 2 y, x = y^{2} + 2

What is the integral from 1 to 3 of sin(x^3+2) ?
The integral from 1 to 3 of sin(x^3+2) is