What is the derivative of x^4-2x^3+3x+1 ?

The derivative of x^4-2x^3+3x+1 is 4x^3-6x^2+3

What is the first derivative of x^4-2x^3+3x+1 ?

The first derivative of x^4-2x^3+3x+1 is 4x^3-6x^2+3

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\frac{d}{d x} (x^{4} - 2 x^{3} + 3 x + 1)

4 x^{3} - 6 x^{2} + 3

Solution steps

\frac{d}{d x} (x^{4} - 2 x^{3} + 3 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (2 x^{3}) + \frac{d}{d x} (3 x) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (1) = 0

= 4 x^{3} - 6 x^{2} + 3 + 0

Simplify

= 4 x^{3} - 6 x^{2} + 3

\int \frac{2 - 5 e ^{- x}}{e ^{- x}} d x

\int x^{7} (x^{8} - 9)^{4} d x

\int sin^{2} (θ) cos^{2} (θ) d θ

x \to 0 lim (\frac{1}{x} - \frac{1}{e ^{x} - 1})

\int x e d x

What is the derivative of x^4-2x^3+3x+1 ?
The derivative of x^4-2x^3+3x+1 is 4x^3-6x^2+3
What is the first derivative of x^4-2x^3+3x+1 ?
The first derivative of x^4-2x^3+3x+1 is 4x^3-6x^2+3