What is the integral from 0 to 0.5 of 250x ?

The integral from 0 to 0.5 of 250x is 31.25

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integral from 0 to 0.5 of 250x

\int_{0}^{0.5} 250 x d x

31.25

Solution steps

\int_{0}^{0.5} 250 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 250 \cdot \int_{0}^{0.5} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{0.5}

= 250 [\frac{x ^{2}}{2}]_{0}^{0.5}

Simplify

= 250 [0.5 x^{2}]_{0}^{0.5}

Compute the boundaries:

0.125

= 250 \cdot 0.125

Simplify

= 31.25

f (x) = \frac{x ^{3}}{3} + 6 x^{2} + 36 x + 9

\int \frac{x}{1 + 2 x} d x

\frac{d}{d x} (- (x + 3) (x - 9)^{2})

\int x \cdot e^{x y} d y

\int 16 x e^{4 x} d x

What is the integral from 0 to 0.5 of 250x ?
The integral from 0 to 0.5 of 250x is 31.25