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Popular >

integral of 8y^{-3}

Solution

\int 8 y^{- 3} d y

Solution

- \frac{4}{y ^{2}} + C

Solution steps

\int 8 y^{- 3} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int y^{- 3} d y

Apply the Power Rule

: - \frac{1}{2 y ^{2}}

= 8 (- \frac{1}{2 y ^{2}})

Simplify

8 (- \frac{1}{2 y ^{2}}) : - \frac{4}{y ^{2}}

= - \frac{4}{y ^{2}}

Add a constant to the solution

= - \frac{4}{y ^{2}} + C

Popular Examples

tangent of f(x)= 8/(x^2+4),\at x=4 tangent of

f (x) = \frac{8}{x ^{2} + 4}, at x = 4

(\partial)/(\partial y)(x^2+y^2-4y)

\frac{\partial}{\partial y} (x^{2} + y^{2} - 4 y)

integral of xarctan(16x)

\int x arctan (16 x) d x

(\partial)/(\partial y)(x+x/(x^2+y^2))

\frac{\partial}{\partial y} (x + \frac{x}{x ^{2} + y ^{2}})

(dy)/(dx)=4e^{-3x}

\frac{d y}{d x} = 4 e^{- 3 x}

Frequently Asked Questions (FAQ)

What is the integral of 8y^{-3} ?
The integral of 8y^{-3} is -4/(y^2)+C