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Popular >

y^'-1=y^2

Solution

y^{^{'}} - 1 = y^{2}

Solution

y = tan (t + c_{1})

Solution steps

y^{'} (t) - 1 = y^{2}

Solve separable ODE:

y = tan (t + c_{1})

y = tan (t + c_{1})

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Frequently Asked Questions (FAQ)

What is the solution for y^'-1=y^2 ?
The solution for y^'-1=y^2 is y=tan(t+c_{1})