What is the tangent of f(x)=x^2-2x,\at x=3 ?

The tangent of f(x)=x^2-2x,\at x=3 is y=4x-9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=x^2-2x,\at x=3

tangent of

f (x) = x^{2} - 2 x, at x = 3

y = 4 x - 9

Solution steps

Find the tangent point:

(3, 3)

Find the slope of

f (x) = x^{2} - 2 x : \frac{df ( x )}{d x} = 2 x - 2

Compute the slope of

f (x) = x^{2} - 2 x

x = 3 : m = 4

Find the line with slope m=

4

and passing through

(3, 3) : y = 4 x - 9

y = 4 x - 9

\frac{\partial}{\partial y} (e^{x} + y e^{x y})

\frac{\partial}{\partial x} (e^{y} + x + x^{2} + 2)

\frac{d y}{- y ln ( \frac{y}{k} )} = c d x

\frac{d y}{d x} + 3 y = 30

y^{^{''}} + 9 y = - 6 tan (3 x)

What is the tangent of f(x)=x^2-2x,\at x=3 ?
The tangent of f(x)=x^2-2x,\at x=3 is y=4x-9