What is area 8-2x,x^3-7x^2+12x,[1,4] ?

The answer to area 8-2x,x^3-7x^2+12x,[1,4] is 37/12

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area 8-2x,x^3-7x^2+12x,[1,4]

area

8 - 2 x, x^{3} - 7 x^{2} + 12 x, [1, 4]

\frac{37}{12}

Decimal Notation

3.08333 \dots

Solution steps

Apply the area formula:

\int_{1}^{4} 8 - 2 x - (x^{3} - 7 x^{2} + 12 x) d x

Solve

\int_{1}^{4} 8 - 2 x - (x^{3} - 7 x^{2} + 12 x) d x : \frac{37}{12}

The area is:

= \frac{37}{12}

h \to 0 lim (h)

\int_{1}^{3} 9 r^{3} ln (r) d r

(sec^{3} (x))^{^{'}}

\int sin (- 7 x) d x

\int_{0}^{2} \frac{x ^{3}}{2} d x

What is area 8-2x,x^3-7x^2+12x,[1,4] ?
The answer to area 8-2x,x^3-7x^2+12x,[1,4] is 37/12