What is the derivative of sqrt(x)-4\sqrt[3]{x} ?

The derivative of sqrt(x)-4\sqrt[3]{x} is 1/(2sqrt(x))-4/(3x^{2/3)}

What is the first derivative of sqrt(x)-4\sqrt[3]{x} ?

The first derivative of sqrt(x)-4\sqrt[3]{x} is 1/(2sqrt(x))-4/(3x^{2/3)}

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derivative of

\frac{1}{2 x} - \frac{4}{3 x ^{\frac{2}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (x) = \frac{1}{2 x}

= \frac{1}{2 x} - \frac{4}{3 x ^{\frac{2}{3}}}

\int s 4^{s} d s

\int_{0}^{\frac{π}{2}} (cos (x))^{2} d x

n = 1 \sum \infty 4^{\frac{1}{2 ^{n}}}

y = (2^{x})^{8}

\int (x^{2} + 2)^{4} 2 x d x

What is the derivative of sqrt(x)-4\sqrt[3]{x} ?
The derivative of sqrt(x)-4\sqrt[3]{x} is 1/(2sqrt(x))-4/(3x^{2/3)}
What is the first derivative of sqrt(x)-4\sqrt[3]{x} ?
The first derivative of sqrt(x)-4\sqrt[3]{x} is 1/(2sqrt(x))-4/(3x^{2/3)}