What is the derivative of (x^2-8/(x-3)) ?

The derivative of (x^2-8/(x-3)) is (x^2-6x+8)/((x-3)^2)

What is the first derivative of (x^2-8/(x-3)) ?

The first derivative of (x^2-8/(x-3)) is (x^2-6x+8)/((x-3)^2)

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\frac{d}{d x} (\frac{x ^{2} - 8}{x - 3})

\frac{x ^{2} - 6 x + 8}{( x - 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 8}{x - 3})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 8 ) ( x - 3 ) - \frac{d}{d x} ( x - 3 ) ( x ^{2} - 8 )}{( x - 3 ) ^{2}}

\frac{d}{d x} (x^{2} - 8) = 2 x

\frac{d}{d x} (x - 3) = 1

= \frac{2 x ( x - 3 ) - 1 \cdot ( x ^{2} - 8 )}{( x - 3 ) ^{2}}

Simplify

\frac{2 x ( x - 3 ) - 1 \cdot ( x ^{2} - 8 )}{( x - 3 ) ^{2}} : \frac{x ^{2} - 6 x + 8}{( x - 3 ) ^{2}}

= \frac{x ^{2} - 6 x + 8}{( x - 3 ) ^{2}}

2 y^{^{''}} - 4 y^{^{'}} + 4 y = e^{x} sec (x)

\int csc^{2} (d) x d x

\int \frac{2 y - 1}{x ^{2} + 1} d y

\int \frac{1}{3 x} d x

What is the derivative of (x^2-8/(x-3)) ?
The derivative of (x^2-8/(x-3)) is (x^2-6x+8)/((x-3)^2)
What is the first derivative of (x^2-8/(x-3)) ?
The first derivative of (x^2-8/(x-3)) is (x^2-6x+8)/((x-3)^2)