What is (\partial)/(\partial θ)(cos^2(θ)) ?

The answer to (\partial)/(\partial θ)(cos^2(θ)) is -sin(2θ)

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(\partial)/(\partial θ)(cos^2(θ))

\frac{\partial}{\partial θ} (cos^{2} (θ))

- sin (2 θ)

Solution steps

\frac{\partial}{\partial θ} (cos^{2} (θ))

Apply the chain rule:

2 cos (θ) \frac{\partial}{\partial θ} (cos (θ))

= 2 cos (θ) \frac{\partial}{\partial θ} (cos (θ))

\frac{\partial}{\partial θ} (cos (θ)) = - sin (θ)

= 2 cos (θ) (- sin (θ))

Simplify

2 cos (θ) (- sin (θ)) : - sin (2 θ)

= - sin (2 θ)

\int (cos (θ))^{3} d θ

\int_{0}^{\frac{π}{3}} x sin (x + y) d y

\int sin (x) + 3 cos (x) d x

\frac{d}{d x} ((1 + 2 x))

x \to 4 - lim (\frac{3}{x ^{2} - 16})

What is (\partial)/(\partial θ)(cos^2(θ)) ?
The answer to (\partial)/(\partial θ)(cos^2(θ)) is -sin(2θ)