What is the derivative of ln(3x^3+2) ?

The derivative of ln(3x^3+2) is (9x^2)/(3x^3+2)

What is the first derivative of ln(3x^3+2) ?

The first derivative of ln(3x^3+2) is (9x^2)/(3x^3+2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

ln (3 x^{3} + 2)

\frac{9 x ^{2}}{3 x ^{3} + 2}

Solution steps

\frac{d}{d x} (ln (3 x^{3} + 2))

Apply the chain rule:

\frac{1}{3 x ^{3} + 2} \frac{d}{d x} (3 x^{3} + 2)

= \frac{1}{3 x ^{3} + 2} \frac{d}{d x} (3 x^{3} + 2)

\frac{d}{d x} (3 x^{3} + 2) = 9 x^{2}

= \frac{1}{3 x ^{3} + 2} \cdot 9 x^{2}

Simplify

\frac{1}{3 x ^{3} + 2} \cdot 9 x^{2} : \frac{9 x ^{2}}{3 x ^{3} + 2}

= \frac{9 x ^{2}}{3 x ^{3} + 2}

\frac{\partial}{\partial r} (2 t + r^{2} cos (t))

\int \frac{e ^{4 x}}{1 + e ^{2 x}} d x

\int_{0}^{\infty} \frac{x}{e ^{x}} d x

\int_{1}^{e} ln (4 x) d x

(1 - x^{2}) \frac{d y}{d x} = x e^{y}

What is the derivative of ln(3x^3+2) ?
The derivative of ln(3x^3+2) is (9x^2)/(3x^3+2)
What is the first derivative of ln(3x^3+2) ?
The first derivative of ln(3x^3+2) is (9x^2)/(3x^3+2)