What is area x=2sqrt(3y),x=0,y=9 ?

The answer to area x=2sqrt(3y),x=0,y=9 is 72sqrt(3)

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area x=2sqrt(3y),x=0,y=9

area

x = 2 3 y, x = 0, y = 9

723

Decimal Notation

124.70765 \dots

Solution steps

Isolate

y

for

x = 2 3 y : y = \frac{x ^{2}}{12} {x \geq 0}

Apply the area formula:

\int_{- 63}^{63} \frac{x ^{2}}{12} - 9 d x

Solve

\int_{- 63}^{63} \frac{x ^{2}}{12} - 9 d x : 723

The area is:

= 723

x \to - 2 lim ((x - 1)^{3})

2 x^{2}

(2 y^{2} - x y) d x + x^{2} d y = 0

\frac{2}{t}

\int (5 x - 8)^{7} d x

What is area x=2sqrt(3y),x=0,y=9 ?
The answer to area x=2sqrt(3y),x=0,y=9 is 72sqrt(3)