What is the sum from n=1 to infinity of 5/(n^3) ?

The sum from n=1 to infinity of 5/(n^3) is converges

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sum from n=1 to infinity of 5/(n^3)

n = 1 \sum \infty \frac{5}{n ^{3}}

converges

Solution steps

n = 1 \sum \infty \frac{5}{n ^{3}}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 5 \cdot n = 1 \sum \infty \frac{1}{n ^{3}}

Apply p-Series Test:

converges

= 5 converges

= converges

sec (x) \frac{d y}{d x} = e^{y + s i n (x)}

\int \frac{x}{x ^{2} + 7} d x

\frac{\partial}{\partial x} (- 4 x^{2})

(- e^{x})^{^{'}}

2 x^{2} y^{^{'}} = y^{^{'}} + 6 x e^{- y}

What is the sum from n=1 to infinity of 5/(n^3) ?
The sum from n=1 to infinity of 5/(n^3) is converges