What is the tangent of f(x)= 1/(4+3x),(2, 1/10) ?

The tangent of f(x)= 1/(4+3x),(2, 1/10) is y=-3/100 x+4/25

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tangent of f(x)= 1/(4+3x),(2, 1/10)

tangent of

f (x) = \frac{1}{4 + 3 x}, (2, \frac{1}{10})

y = - \frac{3}{100} x + \frac{4}{25}

Solution steps

Find the slope of

f (x) = \frac{1}{4 + 3 x} : \frac{df ( x )}{d x} = - \frac{3}{( 4 + 3 x ) ^{2}}

Compute the slope of

f (x) = \frac{1}{4 + 3 x}

(2, \frac{1}{10}) : m = - \frac{3}{100}

Find the line with slope m=

- \frac{3}{100}

and passing through

(2, \frac{1}{10}) : y = - \frac{3}{100} x + \frac{4}{25}

y = - \frac{3}{100} x + \frac{4}{25}

- 4 e^{t}

e^{x} y^{^{'}} = e^{- y} + e^{2 x - y}

\frac{1}{x - 1}, 19

\int cos^{3} (x) \frac{1}{sin ( x )} d x

What is the tangent of f(x)= 1/(4+3x),(2, 1/10) ?
The tangent of f(x)= 1/(4+3x),(2, 1/10) is y=-3/100 x+4/25