What is the solution for y^'+2y=5y^3 ?

The solution for y^'+2y=5y^3 is y=sqrt(2/(-e^{4t+c_{1))+5}},y=-sqrt(2/(-e^{4t+c_{1))+5}}

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y^'+2y=5y^3

y^{^{'}} + 2 y = 5 y^{3}

y = \frac{2}{- e ^{4 t + c_{1}} + 5}, y = - \frac{2}{- e ^{4 t + c_{1}} + 5}

Solution steps

y^{'} (t) + 2 y = 5 y^{3}

Solve Bernoulli ODE:

y = \frac{2}{- e ^{4 t + c_{1}} + 5}, y = - \frac{2}{- e ^{4 t + c_{1}} + 5}

y = \frac{2}{- e ^{4 t + c_{1}} + 5}, y = - \frac{2}{- e ^{4 t + c_{1}} + 5}

y^{^{''}} - 2 y^{^{'}} + y = 2 x e^{2 x} + 6 e^{x}

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What is the solution for y^'+2y=5y^3 ?
The solution for y^'+2y=5y^3 is y=sqrt(2/(-e^{4t+c_{1))+5}},y=-sqrt(2/(-e^{4t+c_{1))+5}}