What is the derivative of ln(x^3-2x) ?

The derivative of ln(x^3-2x) is (3x^2-2)/(x^3-2x)

What is the first derivative of ln(x^3-2x) ?

The first derivative of ln(x^3-2x) is (3x^2-2)/(x^3-2x)

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derivative of

ln (x^{3} - 2 x)

\frac{3 x ^{2} - 2}{x ^{3} - 2 x}

Solution steps

\frac{d}{d x} (ln (x^{3} - 2 x))

Apply the chain rule:

\frac{1}{x ^{3} - 2 x} \frac{d}{d x} (x^{3} - 2 x)

= \frac{1}{x ^{3} - 2 x} \frac{d}{d x} (x^{3} - 2 x)

\frac{d}{d x} (x^{3} - 2 x) = 3 x^{2} - 2

= \frac{1}{x ^{3} - 2 x} (3 x^{2} - 2)

Simplify

\frac{1}{x ^{3} - 2 x} (3 x^{2} - 2) : \frac{3 x ^{2} - 2}{x ^{3} - 2 x}

= \frac{3 x ^{2} - 2}{x ^{3} - 2 x}

y^{^{'}} = - \frac{1}{40} y

7 e^{- x}

\frac{d y}{d x} + \frac{1}{2} y = 0

\int sin (3 x) + 10 cos (x) d x

g (x) = x

What is the derivative of ln(x^3-2x) ?
The derivative of ln(x^3-2x) is (3x^2-2)/(x^3-2x)
What is the first derivative of ln(x^3-2x) ?
The first derivative of ln(x^3-2x) is (3x^2-2)/(x^3-2x)