What is the derivative of 8cos(t)-9sin(t) ?

The derivative of 8cos(t)-9sin(t) is -8sin(t)-9cos(t)

What is the first derivative of 8cos(t)-9sin(t) ?

The first derivative of 8cos(t)-9sin(t) is -8sin(t)-9cos(t)

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derivative of

8 cos (t) - 9 sin (t)

- 8 sin (t) - 9 cos (t)

Solution steps

\frac{d}{d t} (8 cos (t) - 9 sin (t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (8 cos (t)) - \frac{d}{d t} (9 sin (t))

\frac{d}{d t} (8 cos (t)) = - 8 sin (t)

\frac{d}{d t} (9 sin (t)) = 9 cos (t)

= - 8 sin (t) - 9 cos (t)

P (t) = 566 + (37 t^{0.6} - 106)

\int (\frac{1}{x ^{2}} - x^{2} - \frac{1}{3}) d x

\int \frac{2 x}{x ^{2} - 2 x - 3} d x

\frac{d y}{d x} = e^{4 x}

x^{2} e^{- x^{2}}

What is the derivative of 8cos(t)-9sin(t) ?
The derivative of 8cos(t)-9sin(t) is -8sin(t)-9cos(t)
What is the first derivative of 8cos(t)-9sin(t) ?
The first derivative of 8cos(t)-9sin(t) is -8sin(t)-9cos(t)