What is the integral of sin(3)(x) ?

The integral of sin(3)(x) is 1/2 sin(3)x^2+C

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integral of sin(3)(x)

\int sin (3) (x) d x

\frac{1}{2} sin (3) x^{2} + C

Solution steps

\int sin (3) x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= sin (3) \cdot \int x d x

Apply the Power Rule

: \frac{x ^{2}}{2}

= sin (3) \frac{x ^{2}}{2}

Simplify

sin (3) \frac{x ^{2}}{2} : \frac{1}{2} sin (3) x^{2}

= \frac{1}{2} sin (3) x^{2}

Add a constant to the solution

= \frac{1}{2} sin (3) x^{2} + C

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What is the integral of sin(3)(x) ?
The integral of sin(3)(x) is 1/2 sin(3)x^2+C