What is the derivative of x^4+e^{-x} ?

The derivative of x^4+e^{-x} is 4x^3-e^{-x}

What is the first derivative of x^4+e^{-x} ?

The first derivative of x^4+e^{-x} is 4x^3-e^{-x}

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\frac{d}{d x} (x^{4} + e^{- x})

4 x^{3} - e^{- x}

Solution steps

\frac{d}{d x} (x^{4} + e^{- x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (e^{- x})

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (e^{- x}) = - e^{- x}

= 4 x^{3} - e^{- x}

x \to 0 lim (2 x + 4)

x \to 0 lim (9 x - 6)

\int - cos (x) + sin (x) + C d x

\frac{d ^{3} x}{d t ^{3}} - 3 x = 0

y + 3 y^{4} = (y^{6} + 3 x) \frac{d y}{d x}

What is the derivative of x^4+e^{-x} ?
The derivative of x^4+e^{-x} is 4x^3-e^{-x}
What is the first derivative of x^4+e^{-x} ?
The first derivative of x^4+e^{-x} is 4x^3-e^{-x}