What is (\partial)/(\partial x)(8x^2+4y) ?

The answer to (\partial)/(\partial x)(8x^2+4y) is 16x

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(\partial)/(\partial x)(8x^2+4y)

\frac{\partial}{\partial x} (8 x^{2} + 4 y)

16 x

Solution steps

\frac{\partial}{\partial x} (8 x^{2} + 4 y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (8 x^{2}) + \frac{\partial}{\partial x} (4 y)

\frac{\partial}{\partial x} (8 x^{2}) = 16 x

\frac{\partial}{\partial x} (4 y) = 0

= 16 x + 0

Simplify

= 16 x

\int (x^{5} + 2)^{2} d x

\int_{0}^{2} 9 e^{- 2 x} d x

n = k \sum \infty \frac{1}{2 ^{n}}

\int \frac{1}{( 1 - x ^{2} ) ^{2}} d x

f (x) = \frac{5}{x - 2}, at x = 4

What is (\partial)/(\partial x)(8x^2+4y) ?
The answer to (\partial)/(\partial x)(8x^2+4y) is 16x