What is laplacetransform-5sin(2t) ?

The answer to laplacetransform-5sin(2t) is -(10)/(s^2+4)

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laplacetransform-5sin(2t)

laplace transform

- 5 sin (2 t)

- \frac{10}{s ^{2} + 4}

Solution steps

L {- 5 sin (2 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 5 L {sin (2 t)}

L {sin (2 t)} : \frac{2}{s ^{2} + 4}

= - 5 \cdot \frac{2}{s ^{2} + 4}

Refine

- 5 \frac{2}{s ^{2} + 4} : - \frac{10}{s ^{2} + 4}

= - \frac{10}{s ^{2} + 4}

e^{- x + 1} - e^{- x + 1} x

x \to 3 lim (\frac{1 - 2 x}{x - 3})

f (x) = 2 x + 1

\frac{d y}{d x} - y = e^{3 x}

y = x^{3} - 3 x + 2, (3, 20)

What is laplacetransform-5sin(2t) ?
The answer to laplacetransform-5sin(2t) is -(10)/(s^2+4)