What is the integral from 0 to 2 of 3/(x^2) ?

The integral from 0 to 2 of 3/(x^2) is diverges

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integral from 0 to 2 of 3/(x^2)

\int_{0}^{2} \frac{3}{x ^{2}} d x

diverges

Solution steps

\int_{0}^{2} \frac{3}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{2} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{0}^{2}

= 3 [- \frac{1}{x}]_{0}^{2}

Compute the boundaries:

diverges

= diverges

\int 4 x^{3} y^{3} d x

\int (y) d y

\int 9 tan^{3} (x) d x

y = x + 3

\int 3 x^{4} + 6 x^{3} - 3 d x

What is the integral from 0 to 2 of 3/(x^2) ?
The integral from 0 to 2 of 3/(x^2) is diverges