What is derivative of y=(x^2+32sqrt(x))/8 ,x=4 ?

The answer to derivative of y=(x^2+32sqrt(x))/8 ,x=4 is 2

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derivative of y=(x^2+32sqrt(x))/8 ,x=4

derivative of

y = \frac{x ^{2} + 32 x}{8}, x = 4

2

Solution steps

\frac{d}{d x} (\frac{x ^{2} + 32 x}{8}) = \frac{1}{8} (2 x + \frac{16}{x})

Find the value of

\frac{1}{8} (2 x + \frac{16}{x})

for

x = 4 : 2

2

\frac{2}{s ^{3} ( s ^{2} - 9 )}

\frac{d ^{2}}{d x ^{2}} (3 x - \frac{8}{x})

x \to 4 + lim (\frac{x - 4}{∣ x - 4 ∣})

x \to 0 lim (\frac{sin ^{2} ( x )}{x})

\frac{d}{d x} (ln (\frac{∣ x - 1 ∣}{∣ x - 3 ∣}))

What is derivative of y=(x^2+32sqrt(x))/8 ,x=4 ?
The answer to derivative of y=(x^2+32sqrt(x))/8 ,x=4 is 2