What is the integral of 4x^3e^{-x^2} ?

The integral of 4x^3e^{-x^2} is 2(-e^{-x^2}x^2-e^{-x^2})+C

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integral of 4x^3e^{-x^2}

\int 4 x^{3} e^{- x^{2}} d x

2 (- e^{- x^{2}} x^{2} - e^{- x^{2}}) + C

Solution steps

\int 4 x^{3} e^{- x^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int x^{3} e^{- x^{2}} d x

Apply u-substitution

: \int \frac{e ^{u} u}{2} d u

= 4 \cdot \int \frac{e ^{u} u}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \frac{1}{2} \cdot \int e^{u} u d u

Apply Integration By Parts

: e^{u} u - \int e^{u} d u

= 4 \cdot \frac{1}{2} (e^{u} u - \int e^{u} d u)

\int e^{u} d u = e^{u}

= 4 \cdot \frac{1}{2} (e^{u} u - e^{u})

Substitute back

u = - x^{2}

= 4 \cdot \frac{1}{2} (e^{- x^{2}} (- x^{2}) - e^{- x^{2}})

Simplify

4 \cdot \frac{1}{2} (e^{- x^{2}} (- x^{2}) - e^{- x^{2}}) : 2 (- e^{- x^{2}} x^{2} - e^{- x^{2}})

= 2 (- e^{- x^{2}} x^{2} - e^{- x^{2}})

Add a constant to the solution

= 2 (- e^{- x^{2}} x^{2} - e^{- x^{2}}) + C

\frac{d}{d x} (\frac{- x + 1 + x}{x ^{2} - 1})

\int sin^{3} (x) cos^{18} (x) d x

\frac{d}{d x} (\frac{( x ^{3} + y ^{3} )}{( x ^{2} + y ^{2} )})

\frac{d}{d x} (\frac{x + 2}{2})

49 y^{^{''}} + 70 y^{^{'}} + 25 y = 0

What is the integral of 4x^3e^{-x^2} ?
The integral of 4x^3e^{-x^2} is 2(-e^{-x^2}x^2-e^{-x^2})+C