What is the limit as x approaches 3 of (x-3)/(x^2+9) ?

The limit as x approaches 3 of (x-3)/(x^2+9) is 0

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limit as x approaches 3 of (x-3)/(x^2+9)

x \to 3 lim (\frac{x - 3}{x ^{2} + 9})

0

Solution steps

x \to 3 lim (\frac{x - 3}{x ^{2} + 9})

Plug in the value

x = 3

= \frac{3 - 3}{3 ^{2} + 9}

Simplify

= 0

x \to 0 lim (x - 2)

\int \frac{x + 5}{x ^{2} + 4 x + 3} d x

x \to - 8 lim (x + 6)

\int \frac{7 ln ( x + 8 )}{x ^{2}} d x

\frac{d y}{d x} - 2 x y = 10, y (0) = - 8

What is the limit as x approaches 3 of (x-3)/(x^2+9) ?
The limit as x approaches 3 of (x-3)/(x^2+9) is 0