What is the derivative of 1/(2sqrt(r))+1/(7r^{6/7)} ?

The derivative of 1/(2sqrt(r))+1/(7r^{6/7)} is -1/(4r^{3/2)}-6/(49r^{13/7)}

What is the first derivative of 1/(2sqrt(r))+1/(7r^{6/7)} ?

The first derivative of 1/(2sqrt(r))+1/(7r^{6/7)} is -1/(4r^{3/2)}-6/(49r^{13/7)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

\frac{1}{2 r} + \frac{1}{7 r ^{\frac{6}{7}}}

- \frac{1}{4 r ^{\frac{3}{2}}} - \frac{6}{49 r ^{\frac{13}{7}}}

Solution steps

\frac{d}{d r} (\frac{1}{2 r} + \frac{1}{7 r ^{\frac{6}{7}}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d r} (\frac{1}{2 r}) + \frac{d}{d r} (\frac{1}{7 r ^{\frac{6}{7}}})

\frac{d}{d r} (\frac{1}{2 r}) = - \frac{1}{4 r ^{\frac{3}{2}}}

\frac{d}{d r} (\frac{1}{7 r ^{\frac{6}{7}}}) = - \frac{6}{49 r ^{\frac{13}{7}}}

= - \frac{1}{4 r ^{\frac{3}{2}}} - \frac{6}{49 r ^{\frac{13}{7}}}

f (x) = \frac{x ^{2} + 11 x + 24}{x + 8}

\frac{d x}{d t} = x

(ln (x - 1))^{^{'}}

y = \frac{x}{( 1 + x ^{2} )}

\int_{- \infty}^{3} \frac{1}{4 + x ^{2}} d x

What is the derivative of 1/(2sqrt(r))+1/(7r^{6/7)} ?
The derivative of 1/(2sqrt(r))+1/(7r^{6/7)} is -1/(4r^{3/2)}-6/(49r^{13/7)}
What is the first derivative of 1/(2sqrt(r))+1/(7r^{6/7)} ?
The first derivative of 1/(2sqrt(r))+1/(7r^{6/7)} is -1/(4r^{3/2)}-6/(49r^{13/7)}