What is the derivative of (4\sqrt[4]{q})/(1-q) ?

The derivative of (4\sqrt[4]{q})/(1-q) is (1-q+4\sqrt[4]{q}q^{3/4})/(q^{3/4)(1-q)^2}

What is the first derivative of (4\sqrt[4]{q})/(1-q) ?

The first derivative of (4\sqrt[4]{q})/(1-q) is (1-q+4\sqrt[4]{q}q^{3/4})/(q^{3/4)(1-q)^2}

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derivative of

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

\frac{d}{d q} (1 - q) = - 1

Simplify

\frac{d y}{d x} + y = 2 x

\frac{\partial}{\partial y} (\frac{4 y}{x ^{5}})

f (x) = 3 x^{4} - x^{3} - 5 x^{2} + 7, at x = 3

\int - \frac{1}{x + 2} d x

\frac{d y}{d x} = (\frac{( y + 3 )}{( 2 x + 5 )})^{2}

What is the derivative of (4\sqrt[4]{q})/(1-q) ?
The derivative of (4\sqrt[4]{q})/(1-q) is (1-q+4\sqrt[4]{q}q^{3/4})/(q^{3/4)(1-q)^2}
What is the first derivative of (4\sqrt[4]{q})/(1-q) ?
The first derivative of (4\sqrt[4]{q})/(1-q) is (1-q+4\sqrt[4]{q}q^{3/4})/(q^{3/4)(1-q)^2}