What is the solution for y^{''}+6y^'+90y=0 ?

The solution for y^{''}+6y^'+90y=0 is y=e^{-3t}(c_{1}cos(9t)+c_{2}sin(9t))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+6y^'+90y=0

y^{^{''}} + 6 y^{^{'}} + 90 y = 0

y = e^{- 3 t} (c_{1} cos (9 t) + c_{2} sin (9 t))

Solution steps

y^{''} (t) + 6 y^{'} (t) + 90 y = 0

Solve linear ODE:

y = e^{- 3 t} (c_{1} cos (9 t) + c_{2} sin (9 t))

y = e^{- 3 t} (c_{1} cos (9 t) + c_{2} sin (9 t))

f (x) = 2 x^{2}, at x = - 3

\int csc^{2} (6 x + 3) d x

\frac{d}{d x} ((\frac{x}{2})^{4})

\frac{d}{d x} (a ln (2 x + b))

What is the solution for y^{''}+6y^'+90y=0 ?
The solution for y^{''}+6y^'+90y=0 is y=e^{-3t}(c_{1}cos(9t)+c_{2}sin(9t))