What is the derivative of e^{-0.02x} ?

The derivative of e^{-0.02x} is -0.02e^{-0.02x}

What is the first derivative of e^{-0.02x} ?

The first derivative of e^{-0.02x} is -0.02e^{-0.02x}

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\frac{d}{d x} (e^{- 0.02 x})

- 0.02 e^{- 0.02 x}

Solution steps

\frac{d}{d x} (e^{- 0.02 x})

Apply the chain rule:

e^{- 0.02 x} \frac{d}{d x} (- 0.02 x)

= e^{- 0.02 x} \frac{d}{d x} (- 0.02 x)

\frac{d}{d x} (- 0.02 x) = - 0.02

= e^{- 0.02 x} (- 0.02)

Simplify

= - 0.02 e^{- 0.02 x}

18 e^{x^{2}} x

\int \frac{e ^{x}}{2 x} d x

y^{^{''}} + 2 y^{^{'}} + 4 y = 5 sin (t)

\int (- x^{2} - 3 x + 6)^{2} d x

y^{^{''}} - 5 y^{^{'}} + 6 y = 0, y (0) = 0, y^{^{'}} (0) = 0

What is the derivative of e^{-0.02x} ?
The derivative of e^{-0.02x} is -0.02e^{-0.02x}
What is the first derivative of e^{-0.02x} ?
The first derivative of e^{-0.02x} is -0.02e^{-0.02x}