What is the tangent of x^2+xy-y^2=-4,(2,4) ?

The tangent of x^2+xy-y^2=-4,(2,4) is y= 4/3 x+4/3

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tangent of x^2+xy-y^2=-4,(2,4)

tangent of

x^{2} + x y - y^{2} = - 4, (2, 4)

y = \frac{4}{3} x + \frac{4}{3}

Solution steps

Find the slope of

x^{2} + x y - y^{2} = - 4 : \frac{d y}{d x} = \frac{- 2 x - y}{x - 2 y}

Compute the slope of

x^{2} + x y - y^{2} = - 4

(2, 4) : m = \frac{4}{3}

Find the line with slope m=

\frac{4}{3}

and passing through

(2, 4) : y = \frac{4}{3} x + \frac{4}{3}

y = \frac{4}{3} x + \frac{4}{3}

y^{^{'}} = \frac{5 x ^{5} e ^{\frac{y}{x}} + x ^{3} y ^{2}}{x ^{4} y}

\int (\frac{x + 5}{x ^{2} + 5 x + 6}) d x

\frac{1}{s + \frac{1}{2}}

f (x) = \frac{4}{x ^{7}}

4 t - e^{- 3 t}

What is the tangent of x^2+xy-y^2=-4,(2,4) ?
The tangent of x^2+xy-y^2=-4,(2,4) is y= 4/3 x+4/3